Using "Vacant Spaces" based on the opening lead is fallacious. Perhaps the Monty Hall trap was not explained very well. In their book, "Countdown to Winning Bridge", Tim Bourke and Marc Smith blow the concept of using vacant spaces based on the opening lead out of the water.
At the risk of breaking copyright, here is how you blow it away (this is a quote from pages 75-76 -- for the description of the Monty Hall Trap and other good commentary on the hand in question, you will have to buy or borrow the book!):
Often, you cannot get a complete count of the hand, but you can gather sufficient information to make an 'educated guess' -- an informed decision that will be right most of the time. Such choices are often based on the 'Theory of Vacant Spaces.' The premise for this theory is that if West has, for example, eight unknown cards and East has only four, then West is twice as likely (8 to 4 or 2 to 1) to hold a specific missing card.
This is absolutely true. However, a little learning can be a dangerous thing. Consider the following hand from a team-of-four match:
The bidding goes 1
♦ by North, 3NT by South and the opening lead is the
♠5
East wins the
♠Q and returns the 9. West overtakes with the
♠10 and you duck again. A third round of spades forces dummy's ace as East discards a heart. If you misguess the diamonds, your contract will fail. How do you tackle the diamonds. West has five spades to East's two, and thus East has eleven non-spades (or vacant spaces) to West's eight. It is therefore obviously the right percentage play to cash the
♦A and then finesse through East for the
♦Q on the second round... Or is it?
Before deciding, take the North seat at the second table in the same match. This time the bidding is:
(I have not repeated the hand, it is exactly as above.) 1NT by North, 3NT by South.
North-South at this table are playing a 12-14 1NT, so you become declarer from the North seat in the same 3NT contract.
East leads the
♥4 and you duck your ace until the third round, discovering in the process that West has only a doubleton heart. How do you tackle the diamonds? Since East has five hearts to West's two, West has eleven non-hearts (or vacant spaces) to East's eight. It is therefore obviously the right percentage play to cash the
♦K and then finesse through West for the
♦Q on the second round...
Ah! We seem to have been here before. One of these two declarers is destined to go down, yet both have apparently taken the correct line of play. How curious! This situation is often called the 'Monty Hall Trap' after...
(Explanation of the Monty Hall Trap omitted.)
This scenario exemplifies a classic probability trap -- treating biased information as random. In the game show context, Monty Hall showed the contents of Door Two because it contained a booby prize. The information itself had a direct bearing on whether you received it, and that must be taken into account when assessing its value. ...
Returning to the hand above, we can see that each declarer is faced with a similar problem, but that the information available apparently suggests opposite lines of play. Clearly, if both declarers base their play on 'vacant spaces theory' using only the information provided by the opening lead, one will go down. The reason for this is that the distribution of the suit that was led is biased information. It is not random at all. What has really happened? Yes, the defender on lead led his longest suit. That is a common enough occurrence, so why should you be surprised because he has more cards in that suit than his partner?
... (There is more -- buy the book, it is very well written.)