Cue the Uncertain Value
#1
Posted 2016-August-12, 08:06
In that scenario, Opener has one call to show whatever he wants to show. What, then, is an efficient super-accept approach?
When Opener will likely have 7 interesting features, showing all 7 is impossible at this level. The most efficient method seems to be to show the feature that is uncertain in value.
Consider my hand:
♠A ♥A109x ♦KQxx ♣AKxx
Aces, and to a large degree Kings, clearly have value. The two suspect values are the diamond Queen and the spade shortness. (If the hand were the same honors and 2-4-3-4 or 2-4-4-3 shape, the doubleton would be the uncertain shortness value).
In that context, the ideal approach, IMO, is to cuebid the uncertain value.
Partner had ♠xxx ♥KQxxx ♦Axx ♣xx. He likes all of my Aces and Kings, wherever they happen to be. Consider shortness and Queens, though:
1. He loves a diamond Queen, likes a spade Queen, but hates a club Queen.
2. He loves spade shortness, likes diamond shortness, but hates club shortness.
How, then, to unwind this?
There seem to be two general approaches worth considering. Shortness then Queen, or Queen then shortness. Not sure which is better first, but suppose we randomly call one the "A" value and the other the "B" value. "A" could be shortness ("B" then Queen), or "A" could be Queen ("B" then shortness). A fair approach:
2NT-P-3♦-P-3♠ = super-accept, "A" value in spades. 3NT then asks for the "B" value, with 4♣ = club "B" value, 4♥ = diamond "B" value (maintains right-siding)
2NT-P-3♦-P-3NT = "A" value in clubs with a "B" value somewhere. 4♣ asks where. 4♦ = diamond "B" value (wrong-sided, but whatever), 4♥ = spade "B" value
2NT-P-3♦-P-4♣ = "A" value in diamonds, "B" value in clubs
2NT-P-3♦-P-4♥ = "A" value in diamonds, "B" value in spades (avoids wrong-siding)
There are more options not yet defined, but the approach ends up, summarized, as follows:
1. Show the spade "A" value with 3♠ and then show the "B" value if asked by relay
2. Show the club "A" value with 3NT and then show the "B" value if asked by relay
3. Immediately show the diamond "A" value by identifying the "B" value at the four-level
4. If you have space to skip over the one-under call, do so.
With the actual hand prompting this discussion:
2NT-P-3♦-P-4♥ (if "A" value is the side Queen and "B" the short spade, Opener shows this hand
2NT-P-3♦-P-3♠(if "A" value is shortness)-P-3NT-P-4♥("B" value in diamonds, but skip 4♦ if space to do so)
-P.J. Painter.
#2
Posted 2016-August-12, 08:12
-P.J. Painter.
#3
Posted 2016-August-12, 15:20
Would it not solve the so-called dilemmas you have posed in the OP or the rejoinder?
#4
Posted 2016-August-12, 21:34
Second, though, the other plausible sequences create their own (worse) issues. For instance, a 2C overbid followed by what?
-P.J. Painter.
#5
Posted 2016-August-14, 05:36
#6
Posted 2016-August-14, 08:17
Zelandakh, on 2016-August-14, 05:36, said:
Very interesting. What does LTTC mean?
#7
Posted 2016-August-14, 12:12
2NT-3D-?
3S=UES
3NT=cue of spade Queen. 4C asks for doubleton (4♢ diamond doubleton, 4♡ club).
4♧=club Queen. 4♢ retransfer, 4♡ asks for doubleton.
4♢=diamond Queen, club doubleton
4♡=diamond Queen, spade doibleton
-P.J. Painter.
#8
Posted 2016-August-14, 16:44
#9
Posted 2016-August-14, 17:55
nullve, on 2016-August-14, 16:44, said:
I have difficulty contructing a true superaccept with two side Queens and no UES.
The best I can get to, in support of spades, might be AKxx-KQx-KQxx-Ax. But, I would upgrade that to open 2C...2NT. Two Quuens outside just won't occur for me. Or it will be rare.
-P.J. Painter.
#10
Posted 2016-August-17, 05:18
Vampyr, on 2016-August-14, 08:17, said:
LTTC is usually an abbreviation for Last Train to Clarksville, which in turn is commonly shortened to Last Train.
#11
Posted 2016-August-26, 01:32
kenrexford, on 2016-August-12, 08:12, said:
Lucky you didnt accept with 3♠ then --- not playing your alien stuff, he might have passed that, too...